文章詳情頁
oracle中關于null排序的問題
瀏覽:106日期:2023-11-20 10:00:00
問題描述:在處理一般的數據記錄中,對于數字類型的字段,在Oracle的排序中,默認把null值做為大于任何數字的類型,當然對于varchar2類型的字段,默認也是該處理方式,但是客戶要求排序的過程中,需要把null的字段默認排在前邊(從?。?gt;大)。一般的order by xxxx,無法解決。問題解決:方案1:可以使用復雜的使用sql:select * from (select a.*,rownum as my_sys_rownum from (select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl(ZBTS, '0'),nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),nvl(ADDRESS,' '),BDZID from V_BDZ where; rownum<2000 and ZBRL is null) aunionselect b.*,rownum+(select count(*) from (select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl(ZBTS, '0'),nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),nvl(ADDRESS,' '),BDZID from V_BDZ where; rownum<2000 and ZBRL is null)) as my_sys_rownum from (select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl(ZBTS, '0'),nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),nvl(ADDRESS,' '),BDZID from V_BDZ where; rownum<2000 and ZBRL is not null order by ZBRL ) b)order by my_sys_rownum desc方案2:可以利用oracle中可以對order by中對比較字段做設置的方式來實現: 如:; ……order by nvl( aaa,'-1')
排行榜
